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The probability of generating a gene coding for a cytochrome c enzyme composed of 101 amino acid residuals is 2 chances in 1065 tries.1

 

                   This can be pictured as selecting one specific hydrogen nucleus out of                      114 million suns given two draws.2

 

          The probability of generating a gene coding for a specific enzyme composed of 150 amino acid residuals is approximately 1 chance in 1077 tries.3

 

                   This can be pictured as drawing one specific proton or neutron out of a            thousandth of the visible universe given one draw.4

 

          The probability of generating a gene coding for a specific enzyme composed of 150 amino acid residuals plus three specific amino acid residuals is approximately 1 chance in 8x1080 tries.5

 

                   This can be pictured as drawing one specific proton or neutron out of           eight visible universes given one draw.6

 

 

ENDNOTES

 

1. H. P. Yockey, “A calculation of the probability of spontaneous biogenesis by information theory.”  J.             Theor. Bio., 67 (1977), 387.

                        &

            J. Reidhaar-Olson and R. Sauer, “Functionally Acceptable Substitutions in Two α-Helical             Regions of λ Repressor.” Proteins: Structure, Function, and Genetics, 7 (1990), 315.

 

2. Mass of sun: 1.989x1030 kilograms = 1.989x1033 grams

      The mass of the sun is ~73% hydrogen

      Mass of hydrogen in the sun: ~0.73 x 1.989x1033 grams = ~1.45x1033 grams hydrogen

      ~1.45x1033 grams hydrogen x 6.022x1023 atoms/mole = ~8.73x1056 atoms or nucleoli of hydrogen in the sun

     1065/~8.73x1056  hydrogen atoms per sun = ~1.14 108 suns = ~114 million suns

 

3. D. Axe, “Estimating the Prevalence of Protein Sequences Adopting Functional Enzyme Folds,” Journal of Molecular Biology 2004 Aug 27; 341 (5): 1295-1315.

 

4.  1077 tries x 10-80 baryons/visible universe = 1/1,000 of the visible universe

 

5.  1077 tries x  8x103 tries = 8x1080 tries

 

6. 8x1080 tries x 10-80 baryons/visible universe = 8 visible universes

 

 

                                                                                                            Fredric P. Nelson, MD   ©  2025

 
 
 

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